OK....What?!


I've just started watching this and I'm already confused. In the opening scenes, the bad guys invade the guy's house and take hostages. When S.W.A.T. arrives, the home owner (also a bad guy, I know)has a gun too! Why? More importantly why does he point it at the front door when he knows the cops were coming in? (he would have been killed immediately in the real world). Also why would the bad guys allow him to get a gun in the first place!? They weren't with him? He's the one they want the $$ from, why would they let him out of their sight? The whole thing makes NO SENSE AT ALL! Sure there are hypothetical scenarios where stuff could have happened between scenes, but to not SHOW anything makes any speculation a moot point. How stupid!

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Like when they go into the building where there is a hostage and the SWAT guy gives the complete stranger a LOADED GUN and says its for his protection- WTF??? That would NEVER happen

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That stranger was a cop, or, rent-a-cop

thanks

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This is garbage. I've spent valuable life time that i will never get back. Nuff said.

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Also, when they were at the shooting range and the guy was asked to fire upside down.. and the bullet drop was given as the explanation as to why his shot hit too HIGH on the target. As though gravity becomes inverted when you're upside down. This is one of the most idiotic things I have seen in any film.

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She says the bullet is heavier than a regular bullet, and therefore it drops more.
This is basic 10th grade physics. If all things equal, 2 objects of different mass will fall at the same speed. [actually acceleration but yeah.]

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Maybe higher mass=slower muzzle velocity which would result in more drop in a given time because the bullet hasn't traveled as far. As an extreme example imagine throwing a bullet at the target; no matter how hard you threw it would fall far below it before hitting it because of the lower speed.
I have no idea why I'm trying to make sense in this dumb movie. Also, it was clear that they promised the city of Detroit that they wouldn't make their city look bad in order to get their cooperation, thus no acknowledgement that Detroit is one of the most crime-ridden cities in the country!;-)

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The point I'm making is that the guy hit the target right side up but hit too high upside down. Lower velocity from a heavier round would decrease the distance which the sight needs to be calibrated for, sure, but whether the gun is upside down or not makes absolutely no difference. This means that, if the second round was heavier/slower, it would have dropped off before the previous one, but then it would still have hit lower, not higher on the target.

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Okay...I think I can explain what is supposed to have happened.

I set my scope for a target 500 yards away. To do that I have to adjust the scope so that my gun is shooting 5 inches higher than the target because the bullet will drop 5 inches in the 500 yards.

Now imagine I turn the gun upside down.... the bullet will still drop 5 inches over the distance, but the fact that the scope is also upside down will not be correctly adjusted for that 5 inch drop it will be set as if the bullet is going to rise 5 inches... so I would end up being off by 10 inches from the target, twice the actual drop of the bullet because my gun was actually aiming high in the scope but because it was upside down is really aiming low...

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