MovieChat Forums > Heartless (2010) Discussion > What's with the extra-strong Molotov coc...

What's with the extra-strong Molotov cocktails?


When a bottle with liquid is thrown and gets broken on the ground, the law of inertia dictates that the bottle's content will be splashed mainly in the direction of the throw. In this case, the flammable liquid would splash on the ground, with only a little bit getting on the person at whose feet the bottle was thrown. Molotov cocktails seem useful mainly against vehicles and buildings, not so much against individual people, who could just roll on the ground to extinguish the fire on their clothes. Even if the fuel in question is something like napalm, it still has to be deployed in such way as to cover the victim, which does not happen in this movie, at least at the death of Jim Sturgess's character, when the bottle is clearly shown being thrown at his feet. If the scriptwriter really wanted to use some sort of fire-based weapon, he should have better employed flamethrowers. Or make the anarchists/satanists (these are made to seem equivalent here) kidnap their victims, bind them and burn them leisurely at stake.

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You DO realize this movie has talking Dino's, demon and CGI fire effects, right?

Whining about unrealistic physics is just stupid.

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